Cubes of numbers

Written on 11:14 pm by Vja Students

Is there a number which can be expressed as cubes of two numbers in two different ways? i.e. If A^3+B^3=C^3+D^3=X and A,B,C,D are four different numbers.Find X if present.


Ans:(12n)^3+(n)^3=(10n)^3+(9n)^3=1729n^3 for all n>=1

If you enjoyed this post Subscribe to our feed

2 Comments

  1. Anonymous | 24 February 2008 at 2:20 am

    Not possible.

    [pow(m,3) - 1] can not be expressed as pow(n,3) where m and n are different numbers. The reason is (1/3) is an infinite fraction i.e. number of digits after decimal point are infinite.

     
  2. Akash | 24 February 2008 at 3:41 am

    Ramanujan's number:::--
    (10n)^3+(9n)^3=(12n)^3+(n)^3

     

Post a Comment

On world