Number
Written on 11:27 pm by Vja Students
There are 10 statements written on a piece of paper:
1. At least one of statements 9 and 10 is true.
2. This either is the first true or the first false statement.
3. There are three consecutive statements, which are false.
4. The difference between the numbers of the last true and the first true statement divides the number, that is to be found.
5. The sum of the numbers of the true statements is the number, that is to be found.
6. This is not the last true statement.
7. The number of each true statement divides the number, that is to be found.
8. The number that is to be found is the percentage of true statements.
9. The number of divisors of the number, that is to be found, (apart from 1 and itself) is greater than the sum of the numbers of the true statements.
10. There are no three consecutive true statements.
Find the minimal possible number?
Answer
The number is 420.
If statement 6 is false, it creates a paradox. Hence, Statement 6 must be true.
Consider Statement 2:
- If it is true, it must be the first true statement. Otherwise, it creates a paradox.
- If it is false, it must be the second false statement. Otherwise, it creates a paradox.
In both the cases, Statement 1 is false.
As Statement 1 is false, Statement 9 and Statement 10 both are false i.e. there are three consecutive true statements.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
False | - | - | - | - | True | - | - | False | False |
Let\'s assume that Statement 3 is false i.e. there are no three consecutive false statements. It means that Statement 2 and Statement 8 must be true, else there will be three consecutive false statements.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
False | True | False | - | - | True | - | True | False | False |
Also, at least two of Statements 4, 5 and 7 must be true as there are three consecutive true statements.
According to Statement 8, the number that is to be found is the percentage of true statements. Hence, number is either 50 or 60. Now if Statement 7 is true, then the number of each true statement divides the number, that is to be found. But 7 and 8 do not divide either 50 or 60. Hence, Statement 7 is false which means that Statement 4 and 5 are true. But Statement 5 contradicts the Statement 8. Hence, our assumption that Statement 3 is false is wrong and Statement 3 is true i.e. there are 3 consecutive false statements which means that Statement 8 is false as there is no other possibilities of 3 consecutive false statements.
Also, Statement 7 is true as Statement 6 is not the last true statement.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
False | - | True | - | - | True | True | False | False | False |
According to Statement 7, the number of each true statement divides the number, that is to be found. And according to Statement 5, the sum of the numbers of the true statements is the number, that is to be found. For all possible combinations Statement 5 is false.
There 3 consecutive true statements. Hence, Statement 2 and Statement 4 are true.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
False | True | True | True | False | True | True | False | False | False |
Now, the conditions for the number to be found are:
1. The number is divisible by 5 (Statement 4)
2. The number is divisible by 2, 3, 4, 6, 7 (Statement 7)
3. The number of divisors of the number, that is to be found, (apart from 1 and itself) is not greater than the sum of the numbers of the true statements. (Statement 9)
The minimum possible number is 420.
The divisors of 420, apart from 1 and itself are 2, 3, 4, 5, 6, 7, 10, 12, 14, 15, 20, 21, 28, 30, 35, 42, 60, 70, 84, 105, 140, 210. There are total of 22 divisors. Also, the sum of the numbers of the true statements is 22 (2+3+4+6+7=22), which satisfies the third condition.
If 2 is true, it is the first true. So 1 is false. If 2 is false, then it can't be the first false. So 1 is false, thus both 9 and 10 are false.
6 is clearly true, so at least one out of {7,8} is true.
If 3 is true, 7 is true and 8 is false. This implies N >= 42, thus 5 is false. Since 10 is false, there are three consecutive true statements, thus {2,3,4} are true -> N >= 210.
210 = 2*3*5*7 has 16 - 2 = 14 divisors apart from 1 and itself, and 14 <= 2+3+4+6+7, so 9 is really false, and we're ok. So, if 3 is true, N = 210 is the smallest possibility.
If 3 is false, at least one of {4,5} is true, and 8 is true. 8 implies the number is at least 30. If 5 is true, N <= 2 + 4 + 5 + 6 + 7 + 8 = 35. So if 5 is true, 2 and 4 must be false, thus 3 would be true. Impossible.
Therefore 5 is false, 4 is true, and 7 is true (for 10).
7 is true => N >= 168, and 8 is false. Contradiction.
So, 3 is true, and N = 210 is the smallest N possible.
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The answer is 15